00:01
In this question, as we can see, now taking, considering from point, let's say, a to point b, rd and this re are in series.
00:15
So we can write equivalent resistance can be written as, that is, in series, we know that equivalent resistance is added.
00:25
So it will be r d plus r e so that will be 36 so we can write so this will be 36 ome and canceling this now again this rc and this 36 om is parallel with each other so we can write an equivalent canceling this and equivalent so this equivalent let's suppose rr so 1 by r1 plus 1 by rc plus 1 by 36.
01:07
So we can write 1 by rc.
01:11
Now the value of rc is given 12 oms so it will be 1 by 12 plus 1 by 36 by 1 by r1.
01:18
Solving this we will get r1 equals to that is equals to 9 om.
01:24
So we can write now canceling this all from point a to point b that is canceling this all resistance and putting equivalent we will get r1 which is equal to 9 om.
01:41
Now again this ra and rb are sorry ra that is resistance a and resistance b are parallel with each other so we can write equivalent resistance r2 will be equals to 1 by ra plus 1 by rb.
01:58
Now ra is given 1 by 18 and rb is given 4 .5.
02:03
So it will be, so solving this we will get r2 equals to 3 .6 om...