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APPLICATION 5. British Columbia's population $P$, in millions, can be modelled by the equation $P = 2.9(1.0257)^t$, where $t$ is the number of years after 1983. a) What is the population of British Columbia in 1983? b) Determine the population of British Columbia in 1986. c) Determine the population of British Columbia in 1980.

          APPLICATION
5. British Columbia's population $P$, in millions, can be modelled by the equation $P = 2.9(1.0257)^t$, where $t$ is the number of years after 1983.
a) What is the population of British Columbia in 1983?
b) Determine the population of British Columbia in 1986.
c) Determine the population of British Columbia in 1980.
        
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APPLICATION
5. British Columbia's population P, in millions, can be modelled by the equation P = 2.9(1.0257)^t, where t is the number of years after 1983.
a) What is the population of British Columbia in 1983?
b) Determine the population of British Columbia in 1986.
c) Determine the population of British Columbia in 1980.

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Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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Text: APPLICATION 5. British Columbia's population P, in millions, can be modeled by the equation P = 2.9(1.0257)t where t is the number of years after 1983. a) What is the population of British Columbia in 1983? b) Determine the population of British Columbia in 1986 c) Determine the population of British Columbia in 1980
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Transcript

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00:01 Hello, in this question we are given that the population in thousands of cruelty north calorina from 1980 to 2013 can be modeled as 321.
00:15 T is 321 e to the power 0 .0275.
00:26 Okay so where t 0 is corresponding to 980 and furthermore if time increases in years okay t is in years so we need to calculate what was the population of color in 2013 so over here we will put our value of t is equal to 2013 minus 980 so t would be 33 so p can be calculated 321 e 2 the power 0 .0275 into 33.
01:04 So this would be let me equate the value 321 into e to the power 0 .0275 into 33.
01:17 So this is coming out to be 795 .47 this much thousand...
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