00:01
We are given in the question that the well is 20 feet deep.
00:04
So depth of well is 20 feet.
00:16
Now we are given that a snail at a bottom climbs up, climbs up four feet each day and slips two feet from right.
00:40
So we have to find the number of days to reach to the top of the well.
00:46
So let us draw the table.
00:50
Let us consider here the number of days height traveled by the snail and after night how much she sleeps.
01:03
That is the height remaining.
01:17
So on day one, it climbs up to four feet and it slips by two feet.
01:26
So on day two as it will be two.
01:33
4 plus 2 it climbs distance of 6 feet and again it slips by 2 so the remaining distance will be 4.
01:43
Now on 3 day it will be 4 plus 4 that is 8 and slips by 2 that is 8 minus 2 that is 6.
01:52
On 4 day 6 plus 4 that is 10 and slips by 2 so it will be 8.
01:59
On 5th day, 8 plus 4 that is 12 and slips by 2 so it will be 10...