00:01
So i've drawn a graph, a rough sketch of the graph that they gave us in the figure, and i didn't draw all these squiggly lines that just drew the line of best fit that they had.
00:10
And so what we're going to do to find the slope of this line is i'm just going to look at where we're at at 1992, which is about at the seven mark.
00:19
And if we go to 2008, we're about at this 13 mark here.
00:26
So it's about a rise of six units.
00:30
And then, so slope is rise over run.
00:32
So we moved six units in the y direction.
00:37
So we would say the six is the rise.
00:40
And then we moved, we go from 1992 to 2018, or 2008, sorry, that would be 16 years.
00:47
So this would be the run part.
00:49
So this is the rise over the run, which is just the change in y over the change in x.
00:55
And if we divide this and simplify it, this is equal to three eighths.
00:59
So that's the slope of our line.
01:04
And now for part b, we're going to find a equation for our line.
01:08
So again, if we look at this, if we look at this graph, we can see that there's a point at, let's just say, 2008, comma 13.
01:20
So if we were to plug that into an equation, so what we want to do, i guess first i should say, is equation for a line is equal to y is equal to mx plus b, where m is the slope.
01:30
And b is a constant.
01:32
And so what we can do is plug in a point on our graph, knowing this is the slope, 3 eighths, and then solve for b.
01:40
So the point i'm going to plug in is actually going to be 19, or actually 2000, 2000 should be around 10.
01:53
I'm looking at the actual figure...