A uniform rod CD = 0.105 km welded to flat discs 1010 at its ends is connected to a pin joint at point O. Calculate the angular acceleration of the assembly as soon as it is released from rest in the position shown. 0.0768 g m^2 = 0.2025 kg m^2 2 cm
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The moment of inertia of a uniform rod rotating about its center is given by the formula: I = (1/12) * m * L^2 where m is the mass of the rod and L is the length of the rod. Given that the length of the rod CD is 0.105 km, we need to convert it to meters: L = Show more…
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