Question

1 .equ JTAG_UART_BASE, 0xFF201000 2 .text 3 /* executable code follows / 4 5 NUM2STR: 6 ADD SP, SP, #4 7 LDR R5, [SP] // POP R5 = number to print out 8 LDR R9, =JTAG_UART_BASE 9 10 / Programming ... */ 11 12 13 RETURN: 14 BX LR

          1
.equ JTAG_UART_BASE, 0xFF201000
2
.text
3
/* executable code follows */
4
5
NUM2STR:
6
ADD SP, SP, #4
7
LDR R5, [SP] // POP R5 = number to print out
8
LDR R9, =JTAG_UART_BASE
9
10
/* Programming ... */
11
12
13 RETURN:
14
BX LR

Added by Ryan B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adriano Chikande

Step 1

We are to convert a positive number stored in a register (R5, as per the given code) into a string and print it out to the Terminal window using the JTAG UART base address. The conversion process involves dividing the number by 10 repeatedly to extract each digit, Show more…

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ARM Assembly file: Design a subroutine, e.g. NUM2STR, that converts a positive number stored in the register to a string (char array) and prints out the number in the Terminal window. Fill the /*Programming*/ part 1 2 3 4 5 6 7 8 9 10 11 12 13 14 .equ JTAG_UART_BASE, 0xFF201000 .text /* executable code follows */ NUM2STR: ADD LDR LDR SP, SP, #4 R5, [SP] // POP : R5 = number to print out R9, =JTAG_UART_BASE /* Programming */ RETURN: BX LR