00:01
Hello students let's begin with this question.
00:03
This question is based upon the freezing point so we have to arrange some of the given compounds according to their freezing points.
00:11
So the formula used to define this is delta tf is equals to vento factor into freezing point constant into molality.
00:20
So here the freezing point this will depends on the this will depends upon the vento factor i.
00:38
So now let's see first one is 0 .1 molal na3po4.
00:46
So this will dissociate to form 3 na positive plus po4 3 negative so here i is equals to 3 plus 1 is equals to 4.
00:59
For 0 .1 molal c2h5oh.
01:03
This is an alcohol for this i value is equals to 1.
01:07
Then 0 .01 molal co2.
01:14
So here this co2 for this this fento factor is value is equals to 1.
01:20
Next one is the next one is 0 .15 molal nacl.
01:27
So this nacl dissociate to form na positive plus cl negative.
01:34
So here i value is equals to for i is this for this nacl this fento factor is 2 and then is for 0 .2 molal cacl2...