00:01
First of all, let's have a look what all is given in the problem.
00:05
Given is three compounds are given.
00:08
That is fbr, next one is clf and after that is if.
00:17
And what we are supposed to do is we need to find out the, like which of the compound is the most polar.
00:25
For most polar compound, we need to give it as one.
00:30
And for the bond that is most polar, after that followed by two and three, so on.
00:39
So we need to give the numbering to all of these.
00:43
For finding out the polarity of the bond, we should know the electronegativities of these elements.
00:49
See, if we look at the electronegativities of halogens, fluorine, the electronegativity is 4 .0.
00:56
For chlorine, it's 3 .5.
00:59
For bromine it's 2 .8 and for iodine it's 2 .6.
01:06
So let's calculate the polarity of the given bonds...