00:01
Hello students, let's do this question.
00:02
In this question given that the inter -arrival time follows exponential distribution with mean rate of 3 minutes and the service time also follows exponential distribution with mean rate of 4 minute.
00:19
Therefore, the parameter that is inter -arrival time, lambda becomes 1 by 3 minute and mu becomes new equals to 2 by 4 minute.
00:31
Here we take 2 by 4 because 2 identical pump is in station, that is station has 2 identical pump, therefore the value of new becomes 2 by 4.
00:42
Therefore, the waiting space have only one vehicle and 2 pumps.
00:49
Therefore, this model becomes ymm1 model because here arrival rate follows poisson exponential distribution, then service, viscret also follows exponential distribution and number of servers are one.
01:06
Therefore the model becomes yam yam one model.
01:09
Then next we have to find out average number of vehicles in the system.
01:13
So we can find by using ls formula, l .s is equal to lambda upon mu minus lambda, which becomes 1 by 3 divided by 2 by 4 minus 1 by 3...