As a ball rolls down an inclined plane, its velocity v(t) (in cm/sec) at time t (in seconds) is given by v(t) = v0 + at for initial velocity v0 and acceleration a (in cm/sec2). If v(3) = 41 and v(5) = 45, find v0 and a.
Added by Ethan W.
Step 1
From v(3) = 41, we get: 41 = v0 + 3a From v(5) = 45, we get: 45 = v0 + 5a Now we have a system of two equations, and we can solve it to find the values of v0 and a. Subtract the first equation from the second to eliminate v0: Show more…
Show all steps
Close
Your feedback will help us improve your experience
Vysakh M and 68 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
As a ball rolls down an inclined plane, its velocity $v(t)$ (in $\mathrm{cm} / \mathrm{sec}$ ) at time $t$ (in seconds) is given by $v(t)=v_{0}+a t$ for initial velocity $v_{0}$ and acceleration $a$ (in $\mathrm{cm} / \mathrm{sec}^{2}$ ). If $v(2)=16$ and $v(5)=25,$ find $v_{0}$ and $a$
Systems of Equations and Inequatities
Systems of Linear Equations in Two Variables
If a ball is given a push so that it has an initial velocity of 3 m/s down a certain inclined plane, then the distance it has rolled after t seconds is s = 3t + 4t2. (a) Find the velocity after 4s. (b) How long does it take for the velocity to reach 35 m/s?
Vishva S.
If a ball is given a push so that it has an initial velocity of 5 $\mathrm{m} / \mathrm{s}$ rolling down a certain inclined plane, then the distance it has rolled after $t$ seconds is $s=5 t+3 t^{2}$ (a) Find the velocity after 2 s. (b) How long does it take for the velocity to reach 35 $\mathrm{m} / \mathrm{s} ?$
Derivatives
Basic Differentiation Formulas
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
600,000+
Students learning Algebra with Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD