Question

As a sailboat sails 50 m due north, a breeze exerts a constant force $vec{F_1}$ on the boat's sails. This force is directed at an angle west of due north. A force $vec{F_2}$ of the same magnitude directed due north would do the same amount of work on the sailboat over a distance of just 45 m. What is the angle between the direction of $vec{F_1}$ and due north?

Name: As a sailboat sails 50 m due north, a breeze exerts a constant force vecF1 on the boat's sails. This force is directed at an angle west of due north. A force vecF2 of the same magnitude directed due north would do the same amount of work on the sailboat over a distance of just 45 m. What is the angle between the direction of vecF1 and due north?
Uploaded: 2022-09-07T18:20:00-08:00
Duration: 2 min 46 s
Channel: Adi S
Description: As a sailboat sails 50 m due north, a breeze exerts a constant force vecF1 on the boat's sails. This force is directed at an angle west of due north. A force vecF2 of the same magnitude directed due north would do the same amount of work on the sailboat over a distance of just 45 m. What is the angle between the direction of vecF1 and due north?

          As a sailboat sails 50 m due north, a breeze exerts a constant force $vec{F_1}$ on the boat's sails. This force is directed at an angle west of due north. A force $vec{F_2}$ of the same magnitude directed due north would do the same amount of work on the sailboat over a distance of just 45 m. What is the angle between the direction of $vec{F_1}$ and due north?

As a sailboat sails 50 m due north, a breeze exerts a constant force vecF1 on the boat's sails. This force is directed at an angle west of due north. A force vecF2 of the same magnitude directed due north would do the same amount of work on the sailboat over a distance of just 45 m. What is the angle between the direction of vecF1 and due north?

Added by Dean C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

09/07/2022

Step 1

** The work done by a constant force is given by: $W = \overrightarrow{F} \cdot \overrightarrow{s} = Fs\cos\theta$ where: * $W$ is the work done * $\overrightarrow{F}$ is the force vector * $\overrightarrow{s}$ is the displacement vector * $\theta$ is the angle Show more…

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