As an ice skater begins a spin, his angular speed is 3.01 rad/s. After pulling in his arms, his angular speed increases to 5.75 rad/s. Find the ratio of the skater's final moment of inertia to his initial moment of inertia. final / initial =
Added by Michael G.
Step 1
In this case, the skater is the system, and his moment of inertia changes when he pulls in his arms. Angular momentum (L) = moment of inertia (I) x angular speed (ω) So, we can write: I1 x ω1 = I2 x ω2 where I1 is the initial moment of inertia, ω1 is the Show more…
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As an ice skater begins a spin, his angular speed is 3.04 rad/s. After pulling in his arms, his angular speed increases to 5.24 $\mathrm{rad} / \mathrm{s}$ . Find the ratio of the skater's final moment of inertia to his initial moment of inertia.
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