00:01
In this problem, we're going to apply beneath these equations.
00:07
And beneath these equations, its formula is given as t -sub -1 plus one -half p times v -2 initial.
00:37
3 -21 plus p -t times v times 8 of 1 is equal to t -sup 2 plus t -sup 2 plus t -2, 1 1 half p times v2 squared plus p times g times h of 2 2 here p is the fluid density and g is the acceleration due to gravity t sub 1 is the pressure at elevation 1 and v sub 1 is the velocity of elevation one, and h is the height of elevation one, and p sub two is the pressure elevation one, and v sub two is the velocity at elevation one, and h sub two is the height at elevation one.
02:08
So we're giving that t of fluid density is equal to 1 ,000 kilograms grams per meters cubed.
02:34
In z, the velocity at elevation 1, b sub a, is equal to 1 .6 meters per second.
02:48
A sub c is equal to a sub a over 4.
03:07
And the height is 0 .36 meters.
03:13
So that's what we're given.
03:19
So we have to apply the continuity equation at point a and c...