00:01
So in this case, you want to calculate the index of the reflection of a material x and angle of the light makes with the normal in the air.
00:12
So first of all, we are given two angles.
00:16
Theta 1 is 65 degree in the material x.
00:25
Theta 2 is 48 degree in water.
00:36
So basically, theta 1 is the angle in the x and 2 is the angle in water.
00:48
So we know that the refractive index of water and water equals 1 .33.
00:56
And refractive index of air is 1.
00:59
All right, so we're going to use snow law between the material x and water.
01:06
So according to snell's law, n x.
01:17
So this is the reflective index of water.
01:22
There's x, i'm sorry, of theta 1, this is the reflective index of the material x, equals n water, sign of theta 2.
01:44
We want to rearrange for nx.
01:47
Nx equals n the refractive index water multiplied by sine of theta 2, divide by sine of theta 1.
02:04
So then we plug in the value.
02:07
We know that n water, the refractive index of water, is 1 .33.
02:15
And sine 1 is sine 65 degree...