00:01
Hi, as shown in this figure we have a box of mass 67 kg been moved through a distance of 97 meter by applying a force of value to 18 newton that makes an angle 30 with the horizontal.
00:14
The coefficient of kinetic friction between the floor and the box is 0 .1 given and we are asked to calculate the following.
00:23
First to find the work couldn't by the applied force.
00:26
Workeran general formula is f s casteta.
00:30
So here fd cost data we can write.
00:34
Substuting the given data forces to 18 of magnitude.
00:39
Distance mode is 97 multiplied by cost of angle 30 degrees.
00:46
Solving this, we get the work done by the applied forces 18 ,313 june.
00:54
Next part b is to calculate the work done by gravity.
00:58
Work done by gravity work done by the force of gravity is zero in this case since the box moves only in horizontal motion there is no vertical movement involved the vertical motion is zero it is not moving in the vertical plane it moves only in the horizontal direction same goes for the work done by the force of normal the normal force work done by normal is also equal to 0 due to the same reason that there is no vertical movement.
01:43
Next part d is to determine the workuden by friction.
01:48
Workeran by friction is given by the formula force, frictional force multiplied by distance.
01:55
Frictional force has the formula as coefficient of kinetic friction into normal multiplied by d...