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Question 6_) As shown in the figure below, the 6 cm diameter water jet strikes a flat plate containing a hole cm in diameter. Part of the jet passes through the hole and is deflected radially symmetrically from the plate. Assume the density of water is 1,000 kg m-3. a) Calculate the mass flow rate of the jet toward the plate; b) Calculate the jet's deflected part; c) Determine the magnitude and direction of the force required to hold the plate stationary. Explain the details of your solution and calculation steps. Jet $D_1 = 6$ cm $V_1 = 25$ m/s Plate $D_2 = 4$ cm $V_2 = 25$ m/s

          Question 6_)
As shown in the figure below, the 6 cm diameter water jet strikes a flat plate containing a hole
cm in diameter. Part of the jet passes through the hole and is deflected radially symmetrically
from the plate. Assume the density of water is 1,000 kg m-3.
a) Calculate the mass flow rate of the jet toward the plate;
b) Calculate the jet's deflected part;
c) Determine the magnitude and direction of the force required to hold the plate stationary.
Explain the details of your solution and calculation steps.
Jet $D_1 = 6$ cm
$V_1 = 25$ m/s
Plate
$D_2 = 4$ cm
$V_2 = 25$ m/s

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Question 6)
As shown in the figure below, the 6 cm diameter water jet strikes a flat plate containing a hole
cm in diameter. Part of the jet passes through the hole and is deflected radially symmetrically
from the plate. Assume the density of water is 1,000 kg m-3.
a) Calculate the mass flow rate of the jet toward the plate;
b) Calculate the jet's deflected part;
c) Determine the magnitude and direction of the force required to hold the plate stationary.
Explain the details of your solution and calculation steps.
Jet D1 = 6 cm
V1 = 25 m/s
Plate
D2 = 4 cm
V2 = 25 m/s

Added by Sherry M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

06/14/2023

Step 1

The area of the water jet can be calculated using the formula for the area of a circle: A = πr^2, where r is the radius of the circle. In this case, the radius is 3 cm, so the area is A = π(3 cm)^2 = 9π cm^2. Show more…

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As shown in the figure below, the 6 cm diameter water jet strikes a flat plate containing a hole of 4 cm in diameter. Part of the jet passes through the hole and is deflected radially symmetrically away from the plate. Assume the density of water is 1,000 kg m-3. a) Calculate the mass flow rate of the jet toward the plate; b) Calculate the jet’s deflected part; c) Determine the magnitude and direction of the force required to hold the plate stationary. Explain the details of your solution and calculation steps.

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Transcript

00:01 So here we are given the velocity of jet v1 is equals to 30 meter per second.

00:10 Diameter of jet d is equals to 50 mm.

00:15 Area of jet can be calculated as pi by 4 d square that means 0 .054 whole square.

00:24 So let the velocity of the blade is u which we have to find out here.

00:30 Okay velocity of the blade or the plate.

00:34 So effective velocity this should be equals to v1 minus of u.

00:39 Right now mass fluid is tracking the van force secant.

00:43 Let's say it's to be as m dot.

00:46 This can be equals to the density times of area of cross section times of the effective velocity that is v1 minus of u.

00:58 So according to the principle of momentum conservation this force should be equals to the rho a times of v1 minus of u v1 minus of u minus of minus of v1 minus of u.

01:13 Right since the jet is turned completely through the 180 degree of the shift.

01:21 Now work done is equals to force interval displacement.

01:26 So w would be equals to 2 rho a times of v1 minus of u whole square times of u.

01:34 Effective efficiency this can be equals to the output of jet by input of jet.

01:44 Right.

01:44 So what is the output of jet output of jet is nothing but the work done that is 2 rho a times of v1 minus of u that whole square times of u.

01:55 Now what is the input of jet...

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