Question

As you know from the behavior of a nozzle, when a fluid like air is accelerated, the pressure drops. This is exploited in racecars. The air is channeled under the vehicle at the front like a nozzle and then returned to ambient pressure at the rear with a diffuser. For a formula one car traveling at 100 mph, that is 2.0m wide and 5.0m long, the pressure drop is sufficient to double the downforce. The car's mass is 800kg, what pressure must the air have beneath the vehicle, and how fast must the air be traveling under the vehicle? Assume 300K, 100kPa for the ambient air temperature and pressure.

          As you know from the behavior of a nozzle, when a fluid like air is accelerated, the pressure drops.  This is exploited in racecars.  The air is channeled under the vehicle at the front like a nozzle and then returned to ambient pressure at the rear with a diffuser.  For a formula one car traveling at 100 mph, that is 2.0m wide and 5.0m long, the pressure drop is sufficient to double the downforce. The car's mass is 800kg, what pressure must the air have beneath the vehicle, and how fast must the air be traveling under the vehicle?  Assume 300K, 100kPa for the ambient air temperature and pressure.
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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As you know from the behavior of a nozzle, when a fluid like air is accelerated, the pressure drops. This is exploited in racecars. The air is channeled under the vehicle at the front like a nozzle and then returned to ambient pressure at the rear with a diffuser. For a formula one car traveling at 100 mph, that is 2.0m wide and 5.0m long, the pressure drop is sufficient to double the downforce. The car's mass is 800kg, what pressure must the air have beneath the vehicle, and how fast must the air be traveling under the vehicle? Assume 300K, 100kPa for the ambient air temperature and pressure.
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00:01 Hello everyone so here we have been given a string and when we cut so find the acceleration acceleration of rod that we are going to find out so here this is the mass so this is the m t here is the tension t here is the tension is 2 t because tension is inversely proportional to the length so when we just cut down, so at that time this mg is going to be moving like that.
00:42 So this is the pivot point.
00:45 So apart from this pivot point, so this will be the torque...
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