00:01
Hello students, let's see the equation at p1 is equal to 6 mpa, t1 is equal to 50, h1 is given, s1 is given, p2, hf2, hf2 is given, sf2 is given, so we can write s1 is equal to s2.
00:12
So it would be 6 .803 is equal to 13026 plus r2 x2 multiplied by 6 .0568, so from here x2 would be equal to 0 .9208 and h2 would be equal to 417 .46 plus 0 .9206 multiplied by 2258, so this would be equal to 2496 .62 kj divided by kg.
00:39
So change in enthalpy would be equal to h1 minus h2, so that is equal to 3422 .2 minus 2496 .62, so that is equal to 925 .57 kj divided by kg.
01:05
So q heat would be equal to 1 divided by 100 multiplied by 925 .57, so that is equal to 9 .25 kj divided by kg.
01:19
So from here we can calculate the value of w, so that is equal to 921 .220 kj divided by kg, so w would be equal to 9 .21 mw...