Question

A skier with a mass of 50 kg starts from the top of a hill (at rest) at height h above ground. The skier glides down the hill to point A where her velocity is v_A = 20 m/s and continues up a second hill 8 meters high and back down the other side. Her entire trip up to point C is frictionless. At point C she begins stopping and comes to a complete stop 48 meters later at point D. 7) What is the height h of the first hill? h = 12.8 m h = 32.5 m h = 16.5 m h = 28.6 m h = 20.4 m 8) What is the speed of the skier at point B? 0 m/s 12.8 m/s 15.6 m/s 18.3 m/s 20 m/s 9) What is the speed of the skier at point C? 0 m/s 12.8 m/s 15.6 m/s 18.3 m/s 20 m/s 10) When coming down the first hill, at what height off the ground will the SPEED of the skier be half of its value at point A? at a distance h off the ground at a distance .75h off the ground at a distance .5h off the ground at a distance .25h off the ground 11) What is the magnitude of the work done by friction on the skier in stopping her? W = 10000 J W = 11200 J W = 12300 J W = 12300 J W = 12300 J

          A skier with a mass of 50 kg starts from the top of a hill (at rest) at height h above ground. The skier glides down the hill to point A where her velocity is v_A = 20 m/s and continues up a second hill 8 meters high and back down the other side. Her entire trip up to point C is frictionless. At point C she begins stopping and comes to a complete stop 48 meters later at point D.

7) What is the height h of the first hill?
h = 12.8 m
h = 32.5 m
h = 16.5 m
h = 28.6 m
h = 20.4 m

8) What is the speed of the skier at point B?
0 m/s
12.8 m/s
15.6 m/s
18.3 m/s
20 m/s

9) What is the speed of the skier at point C?
0 m/s
12.8 m/s
15.6 m/s
18.3 m/s
20 m/s

10) When coming down the first hill, at what height off the ground will the SPEED of the skier be half of its value at point A?
at a distance h off the ground
at a distance .75h off the ground
at a distance .5h off the ground
at a distance .25h off the ground

11) What is the magnitude of the work done by friction on the skier in stopping her?
W = 10000 J
W = 11200 J
W = 12300 J
W = 12300 J
W = 12300 J

Show more…

A skier with a mass of 50 kg starts from the top of a hill (at rest) at height h above ground. The skier glides down the hill to point A where her velocity is vA = 20 m/s and continues up a second hill 8 meters high and back down the other side. Her entire trip up to point C is frictionless. At point C she begins stopping and comes to a complete stop 48 meters later at point D.

7) What is the height h of the first hill?
h = 12.8 m
h = 32.5 m
h = 16.5 m
h = 28.6 m
h = 20.4 m

8) What is the speed of the skier at point B?
0 m/s
12.8 m/s
15.6 m/s
18.3 m/s
20 m/s

9) What is the speed of the skier at point C?
0 m/s
12.8 m/s
15.6 m/s
18.3 m/s
20 m/s

10) When coming down the first hill, at what height off the ground will the SPEED of the skier be half of its value at point A?
at a distance h off the ground
at a distance .75h off the ground
at a distance .5h off the ground
at a distance .25h off the ground

11) What is the magnitude of the work done by friction on the skier in stopping her?
W = 10000 J
W = 11200 J
W = 12300 J
W = 12300 J
W = 12300 J

Added by Gina O.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

07/24/2023

Step 1

To find the height of the first hill, we can use the conservation of energy principle. The initial potential energy of the skier at the top of the hill is mgh, where m is the mass of the skier, g is the acceleration due to gravity, and h is the height of the hill. Show more…

Show all steps

lock

Thanks for your feedback!

The skier with a mass of 50 kg starts from the top of a hill (at rest) at a height h above the ground. The skier glides down the hill to a point where her velocity is 20 m/s and continues up a second hill, reaching a height and then coming back down the other side. Her entire trip to point C is frictionless. Point C is where she begins stopping and comes to a complete stop 48 meters later at point D. What is the height of the first hill? 12.8 m 32.5 m 16.5 m 28.6 m 20.4 m What is the speed of the skier at point B? 0 m/s 12.8 m/s 15.6 m/s 18.3 m/s 20 m/s What is the speed of the skier at point C? 0 m/s 12.8 m/s 15.6 m/s 18.3 m/s 20 m/s When coming down the first hill, at what height above the ground will the speed of the skier be half of its value at point A? at a distance h off the ground at a distance .75h off the ground at a distance .5h off the ground at a distance .25h off the ground What is the magnitude of the work done by friction on the skier in stopping her? W = 10000 J W = 11200 J W = 12300 J

Play audio

Feedback

Powered by NumerAI

Madhur L and 89 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Transcript

00:01 Hello students, in this question given as the mass is equal to 50 kg.

00:06 Now in the first part of the question we have to calculate the height of the hill.

00:12 So which is moving now we can write the equation va square is equal to v square initial velocity and plus 2gh.

00:22 So va at the point a the velocity is given in this question 20 m per second and the initial velocity is 0 and 2g 9 .8 into h.

00:34 Now after calculation we will get the height of the hill is equal to 20 .38 m.

00:44 Now the option e will be correct.

00:52 In the next question given as we have to calculate the velocity at the point b this is equal to this and point b is at the height 8 m.

01:12 So that will be 8 and minus sign will take it against the gravity.

01:17 So this will be equal to the 20 square minus 2 into 9 .8 into 8.

01:25 So after calculation we will get the velocity at the point b will be equal to the 15 .6 m per second.

01:36 Now the options option c will be correct.

01:42 Sorry this is a question number 7 and this is a question number 8.

01:55 Now in the question number 9 we have to calculate the velocity at the point c.

02:00 So this is will be equal to the vb square plus 2g 8 and now we will substitute all the values 15 .6 whole square and plus 2 into 9 .8 into 8.

02:19 So after calculation we will get the velocity at the point c again will be 20 m per second.

02:26 Now the option option e will be correct...

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later