0320 \cdot t^{15.0}) dt = 0.0320 \cdot \frac{t^{16.0}}{16.0} + C_1$
Now, we need to find the constant $C_1$ using the initial condition $v_z(0) = 4.90$:
$4.90 = 0.0320 \cdot \frac{0^{16.0}}{16.0} + C_1 \Rightarrow C_1 = 4.90$
So, the velocity function
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