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Assignment 10: Solving Logarithmic Equations 1. Solve each of the following. a) $\log_3 x = \log_3 24$ b) $\log x = 3 \log 2$ c) $\log_5 x = \log_5 3 + \log_5 7$ d) $\log_2(x-4) = 4$ e) $\log(2x-4) = 1$ f) $\log_2 (7x+8)= 6$ g) $\log_x 9 = 2$ h) $\log_2(x+2) = -2$

Name: assignment 10 solving logarithmic equations 1 solve each of the following a log3 x log3 24 b log x 3 log 2 c log5 x log5 3 log5 7 d log2x 4 4 e log2x 4 1 f log2 7x8 6 g logx 9 2 h lo 19749
Uploaded: 2022-06-04T20:53:03-08:00
Duration: 5 min 39 s
Channel: Suzanne W.
Description: assignment 10 solving logarithmic equations 1 solve each of the following a log3 x log3 24 b log x 3 log 2 c log5 x log5 3 log5 7 d log2x 4 4 e log2x 4 1 f log2 7x8 6 g logx 9 2 h lo 19749

          Assignment 10: Solving Logarithmic Equations
1. Solve each of the following.
a) $\log_3 x = \log_3 24$
b) $\log x = 3 \log 2$
c) $\log_5 x = \log_5 3 + \log_5 7$
d) $\log_2(x-4) = 4$
e) $\log(2x-4) = 1$
f) $\log_2 (7x+8)= 6$
g) $\log_x 9 = 2$
h) $\log_2(x+2) = -2$

assignment 10 solving logarithmic equations 1 solve each of the following a log3 x log3 24 b log x 3 log 2 c log5 x log5 3 log5 7 d log2x 4 4 e log2x 4 1 f log2 7x8 6 g logx 9 2 h lo 19749

Added by Amy W.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Suzanne W.

06/04/2022

Step 1

Step 1: a) $\log_3 x = \log_3 24$ Since the bases are the same, we can equate the arguments: $x = 24$ Show more…

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Assignment 10: Solving Logarithmic Equations 1. Solve each of the following. a) $\log_3 x = \log_3 24$ b) $\log x = 3 \log 2$ c) $\log_5 x = \log_5 3 + \log_5 7$ d) $\log_2(x-4) = 4$ e) $\log(2x-4) = 1$ f) $\log_2 (7x+8)= 6$ g) $\log_x 9 = 2$ h) $\log_2(x+2) = -2$