Question

Assume a rectangular strip of a material with an electron density of n = 5.8x10^20 cm^-3. The strip is 9 mm wide and 0.4 mm thick, and it is in a magnetic field of 9 T pointing out of the paper plane. The Hall voltage is measured to be 0.8 mV. What was the current during this measurement? State the current in Amp units. ANS: 3.304 e = 1.602x10^-19 D = thickness I = (Den*V) / B

Name: assume a rectangular strip of a material with an electron density of n58x1020 cm 3 the strip is 9 mm wide and 04 mm thick and it is in a magnetic field of 9 t pointing out of the paper plane 85653
Uploaded: 2022-02-11T06:35:43-08:00
Duration: 2 min 5 s
Channel: Prabhu Ramji
Description: assume a rectangular strip of a material with an electron density of n58x1020 cm 3 the strip is 9 mm wide and 04 mm thick and it is in a magnetic field of 9 t pointing out of the paper plane 85653

          Assume a rectangular strip of a material with an electron density of n = 5.8x10^20 cm^-3. The strip is 9 mm wide and 0.4 mm thick, and it is in a magnetic field of 9 T pointing out of the paper plane. The Hall voltage is measured to be 0.8 mV. What was the current during this measurement? State the current in Amp units.

ANS: 3.304
e = 1.602x10^-19
D = thickness
I = (D*e*n*V) / B

Added by Jose Miguel S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

02/11/2022

Step 1

4 mm = 0.4 x 10^-3 m Volume (V) = w x t = 9 x 10^-3 m x 0.4 x 10^-3 m = 3.6 x 10^-6 m^3 Show more…

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Assume a rectangular strip of a material with an electron density of n = 5.8x10^20 cm^-3. The strip is 9 mm wide and 0.4 mm thick, and it is in a magnetic field of 9 T pointing out of the paper plane. The Hall voltage is measured to be 0.8 mV. What was the current during this measurement? State the current in Amp units. ANS: 3.304 e = 1.602x10^-19 D = thickness I = (D*e*n*V) / B