Question

Assume arm ABC is a single rigid body with a mass of 1,000 kg and a moment of inertia of 3,900 kg-m² about its center of mass (located as shown). The angular velocity of the arm is 1.5 rad/sec and the angular acceleration of the arm is 2.0 rad/s² in the position shown. What is the force exerted by the hydraulic cylinder at point B? [Units for your answer will be kN] h1 = 1.9 m; h2 = 2.4 m; d = 1.6 m

          Assume arm ABC is a single rigid body with a mass of 1,000 kg and a moment of inertia of 3,900 kg-m² about its center of mass (located as shown). The angular velocity of the arm is 1.5 rad/sec and the angular acceleration of the arm is 2.0 rad/s² in the position shown. What is the force exerted by the hydraulic cylinder at point B? [Units for your answer will be kN] h1 = 1.9 m; h2 = 2.4 m; d = 1.6 m

Assume arm ABC is a single rigid body with a mass of 1,000 kg and a moment of inertia of 3,900 kg-m² about its center of mass (located as shown). The angular velocity of the arm is 1.5 rad/sec and the angular acceleration of the arm is 2.0 rad/s² in the position shown. What is the force exerted by the hydraulic cylinder at point B? [Units for your answer will be kN] h1 = 1.9 m; h2 = 2.4 m; d = 1.6 m

Added by Mark K.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Hafiz Shahzaib

Step 1

Torque is given by the formula: Torque = Moment of Inertia * Angular Acceleration Torque = 3,900 kg-m^2 * 2.0 rad/s^2 Torque = 7,800 N-m Show more…

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Assume arm ABC is a single rigid body with a mass of 1,000 kg and a moment of inertia of 3,900 kg-m2 about its center of mass (located as shown). The angular velocity of the arm is 1.5 rad/sec and the angular acceleration of the arm is 2.0 rad/s? in the position shown: What is the force exerted by the hydraulic cylinder at point B? [Units for your answer will be kN] hl 1.9 m; h2 = 2.4 m; d = 1.6 m B h2 m hl m Fd m-+d m-