00:01
It's an moving question.
00:01
It says it assumes that 12 % of people are left -handed.
00:04
Suppose 14 people are selected at random.
00:07
Answer each of the questions about, okay.
00:09
So the first thing is to determine the mean and standard deviation of the number of right -handers in the group.
00:15
So here the left -handed is 0 .12.
00:19
So the probability of right -handed, it will be 1 -10 .12.
00:23
That is 0 .88.
00:25
Right.
00:26
Now, the mean here, it will be equal to n.
00:30
Into p that is this one so this will be equal to sorry for right -handed we need to determine right so this will be n 14 into 0 .88 that is 12 .32 and the standard deviation it will be square root of n into p into 1 minus p again we are taking for right -handedness right so this will be 14 into 0 .88 multiplied by 1 minus 0 .88.
01:03
So this will be equal to 1 .22.
01:06
Now we move on to the next part.
01:08
It says to calculate what is the probability that they are not all right -handed.
01:13
All right.
01:14
So here we need to calculate it the probability that they are not all right -handed, which means that the probability of x is equal to 0 for right -handed, right? so we will use the binomial distribution here...