Assume that a procedure yields a binomial distribution with a trial repeated $n = 18$ times. Use either the binomial probability formula (or technology) to find the probability of $k = 3$ successes given the probability $p = 0.27$ of success on a single trial. (Report answer accurate to 4 decimal places.) P(X = k) =
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Step 1: The binomial probability formula is given by: $$P(X = k) = {n \choose k} p^k (1-p)^{(n-k)}$$ where $n$ is the number of trials, $k$ is the number of successes, and $p$ is the probability of success on a single trial. Show more…
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