Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval for a sample of size 112 with 75.9% successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places.< p < Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Added by Sheena P.
Step 1
The formula for the standard error of the sample proportion is: SE = sqrt(p*(1-p)/n) where p is the sample proportion and n is the sample size. Substituting the given values, we get: SE = sqrt(0.759*(1-0.759)/112) = 0.045 Show more…
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