Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval for a sample of size 158 with 71% successes. Enter your answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places. < p <
Added by Josep M.
Step 1
The formula for the standard error of the sample proportion is: SE = sqrt(p*(1-p)/n) where p is the sample proportion and n is the sample size. In this case, p = 0.71 and n = 158, so: SE = sqrt(0.71*(1-0.71)/158) = 0.045 Show more…
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