Assume that a sample is used to estimate a population proportion \( p \). Find the margin of error M.E. that corresponds to a sample of size 347 with \( 61.1 \% \) successes at a confidence level of \( 99.8 \% \). M.E. \( = \) \( \square \) \( \% \) Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places. Round final answer to one decimal place
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The problem states that there are 61.1% successes. To convert this percentage to a proportion, divide by 100: \[ p = \frac{61.1}{100} = 0.611 \] Show more…
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