Question

Assume that, in this market, the quality of cars Xi is distributed as follows: $X_i \sim Uniform[q_1, q_2]$ Note that in the discussion above, we analyzed the version of the Akerlof model where $q_1 = 0$ and $q_2 = 100$. What will be the $E[X_i/P] = \frac{q_2 - q_1}{2}$? 50 25 100 0

          Assume that, in this market, the quality of cars Xi is distributed as follows:
$X_i \sim Uniform[q_1, q_2]$
Note that in the discussion above, we analyzed the version of the Akerlof
model where $q_1 = 0$ and $q_2 = 100$.
What will be the $E[X_i/P] = \frac{q_2 - q_1}{2}$?
50
25
100
0
        
Show more…
Assume that, in this market, the quality of cars Xi is distributed as follows:
Xi ∼ Uniform[q1, q2]
Note that in the discussion above, we analyzed the version of the Akerlof
model where q1 = 0 and q2 = 100.
What will be the E[Xi/P] = (q2 - q1)/(2)?
50
25
100
0

Added by Natasha M.

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Principles of Economics
Principles of Economics
Gregory Mankiw 8th Edition
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Assume that, in this market, the quality of cars x_(i) is distributed as follows: xi ∼ Uniform q_(1),q_(2) Note that in the discussion above, we analyzed the version of the Akerlof model where q_(1)=0 and q_(2)=100. What will be the E[(x_(i))/(P)]=(q_(2)-q_(1))/(2) ? 50 25 100 0 Assume that, in this market, the quality of cars Xi is distributed as follows: Xi ~ Uniform[q1,q2] Note that in the discussion above, we analyzed the version of the Akerlof model where q1 = 0 and q2 = 100. 2 O50 25 O100 O0
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Transcript

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00:01 For this exercise, we are told that the distribution of car prices is symmetric with the mean of 22 ,000 and standard deviation of 2000.
00:11 And we are asked what proportion of cars will be above the mean price.
00:17 For any symmetrical distribution, the mean will always be the 50th percentile.
00:24 If the distribution is symmetrical, the mean will always be right in the center of the distribution, which means that 50 % or half of the cars will be above the mean price and half will be less on the mean price.
00:41 For example, if the distribution is normal, the normal distribution is a good example of a symmetrical distribution...
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