Assume that (Systolic) blood pressure in healthy adults has a normal distribution with mean 112 mmHg and standard deviation 10 mmHg. a) Find the probability that a randomly selected person have a blood pressure between 99 mmHg and 117 mmHg. b) Find a value A such that 99 % of health adults have a blood pressure below A. c) Find the pressure B such that 99 % of health adults have a blood pressure above B.
Added by Keith M.
Step 1
Given that blood pressure follows a normal distribution with mean 112 mmHg and standard deviation 10 mmHg, we need to find the z-scores for 99 mmHg and 117 mmHg. For 99 mmHg: \[ z = \frac{99 - 112}{10} = -1.3 \] For 117 mmHg: \[ z = \frac{117 - 112}{10} = 0.5 Show more…
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