Assume that the speed of automobiles on an expressway during rush hour is normally distributed with a mean of 62 mph and a standard deviation of 5 mph. What percent of cars are traveling slower than 54 mph? The percentage of cars traveling slower than 54 mph is %. (Type an integer or a decimal rounded to two decimal places as needed.)
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The z-score is calculated by subtracting the mean from the value and then dividing by the standard deviation. So, z = (54 - 62) / 5 = -1.6 Show more…
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