00:01
It is given in the question that the two rods, one of copper and one brass are connected each other, each of length 20 centimeters and the diameter 2 centimeters.
00:14
The free end of copper is at 100 degrees celsius and that of brass is at 0 degree celsius.
00:19
It is also given that thermal conductivity of copper is four times thermal conductivity of brass.
00:26
From the diameter i can find the radius as well as the area.
00:30
Which will be 3 .14 piar square, 1 square giving us 3 .14 cm square.
00:39
Now we know that heat transfer from the copper will be equal to the heat transfer to the brass which is further equal to change in heat per unit time the copper is equal to change in heat per unit time of the brass.
01:15
This is further equal to thermal conductivity times area divided by length times change in the temperature.
01:25
Now putting the values, i get k thermal conductivity of copper area divided by length 100 minus t.
01:38
Equals thermal conductivity of brass a divided by length t minus 0.
01:44
T is the temperature of the junction.
01:54
Solving it further, these terms cancel each other.
01:59
Thermal conductivity of copper is 4 times thermal conductivity of brass...