Assume that X is uniformly distributed random variable with mean 8 and variance 12. Find the probability that X is at most 10.4 . 0.075 0.7 0.85 0.3 0.15
Added by Brent F.
Step 1
We can do this by using the formula: Z = (X - μ) / σ where μ is the mean and σ is the standard deviation. In this case, μ = 8 and σ = sqrt(12) = 3.4641. So, we have: Z = (10.4 - 8) / 3.4641 = 0.7483 Show more…
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