00:01
In this question, we have 4 dimes and 2 quarters and they are all distinct.
00:07
Total number of coins is 6 and you select 3 coins.
00:12
In part 1, want to find the number of ways the selections can be made.
00:18
Take note that the 3 coins are selected without replacement and that the order of selection is not important.
00:32
This will be using combination.
00:37
There is n -chus -r.
00:39
So number of ways the selection can be made without any restriction, that will be from the six coins we choose three.
00:48
And that's 20 ways.
00:51
Number of ways the selection can be made if all the coins are dimes.
00:55
So from the four times, we're just going to choose three.
00:59
And so the answer is four...