Question

Assume the gasoline is burned with 99% efficiency in a car engine, with 1% remaining unburned in the exhaust gases as VOCs (volatile organic compounds). If the engine exhausts 16 kg of gases (MW=30) for each kg of gasoline (MW=100), calculate the fraction of VOCs in the exhaust. Give your answer in parts per million.

Name: assume the gasoline is burned with 99 efficiency in a car engine with 1 remaining unburned in the exhaust gases as vocs volatile organic compounds if the engine exhausts 16 kg of gases mw30 46633
Uploaded: 2023-02-16T09:41:14-08:00
Duration: 3 min 49 s
Channel: Madhur L
Description: assume the gasoline is burned with 99 efficiency in a car engine with 1 remaining unburned in the exhaust gases as vocs volatile organic compounds if the engine exhausts 16 kg of gases mw30 46633

          Assume the gasoline is burned with 99% efficiency in a car engine, with 1% remaining unburned in the exhaust gases as VOCs (volatile organic compounds). If the engine exhausts 16 kg of gases (MW=30) for each kg of gasoline (MW=100), calculate the fraction of VOCs in the exhaust. Give your answer in parts per million.

Added by David S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

02/16/2023

Step 1

Given that 99% of the gasoline is burned, 1% remains unburned. \[ \text{Unburned gasoline (VOCs)} = 1\% \text{ of 1 kg} = 0.01 \text{ kg} \] Show more…

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Assume the gasoline is burned with 99% efficiency in a car engine, with 1% remaining unburned in the exhaust gases as VOCs (volatile organic compounds). If the engine exhausts 16 kg of gases (MW=30) for each kg of gasoline (MW=100), calculate the fraction of VOCs in the exhaust. Give your answer in parts per million.