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1) Assume the professor prepares a stock solution by placing 0.025 g (±0.001 g) of Methyl Orange into a 1000.0 mL Class A volumetric flask and then adding deionized water up to the volumetric mark. (a) Explain what are the solute and the solvent in this case? For the solvent, use the specific type as indicated in page 12.

          1) Assume the professor prepares a stock solution by placing 0.025 g (±0.001 g) of Methyl Orange into a 1000.0 mL Class A volumetric flask and then adding deionized water up to the volumetric mark.
(a) Explain what are the solute and the solvent in this case? For the solvent, use the specific type as indicated in page 12.
        
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1) Assume the professor prepares a stock solution by placing 0.025 g (±0.001 g) of Methyl Orange into a 1000.0 mL Class A volumetric flask and then adding deionized water up to the volumetric mark.
(a) Explain what are the solute and the solvent in this case? For the solvent, use the specific type as indicated in page 12.

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Assume the professor prepares a stock solution by placing 0.025g(+-0.001g) of Methyl Orange into a 1000.0mL Class A volumetric flask and then adding deionized water up to the volumetric mark.\n(a) Explain what are the solute and the solvent in this case? For the solvent, use the specific type as indicated in page 12. 1Assume the professor prepares a stock solution by placing 0.025 g (0.001 g of Methyl Orange into a 1000.0 mL Class A volumetric flask and then adding deionized water up to the volumetric mark a) Explain what are the solute and the solvent in this case? For the solvent,use the specific type as indicated in page 12
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Transcript

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00:01 To calculate the concentration of methyl orange after dilution in units of malarity, we need to know the moles of methyl orange, and we need to know the final volume in liters of the solution.
00:19 The moles of methyl orange can be calculated by recognizing that we're taking 4 .07 milliliters of the stock methyl orange solution, 4 .07 .7 mil liters of the stock methyl orange solution, 4 .07.
00:32 Milliliters is 0 .0407 liters, missing one zero, multiplied by its concentration of 139 grams per liter, which we then convert to moles per liter using the molar mass.
01:02 One mole of methyl orange is 327 .33 grams.
01:14 The grams will cancel, the liters will cancel, and will be left with moles of methyl orange.
01:21 We then divide that by the total volume...
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