Assume the random variable x is normally distributed with mean ? = 50 and standard deviation ? = 7. Find the indicated probability. P(x > 36) P(x > 36) =
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The z-score is calculated by subtracting the mean from the value and dividing by the standard deviation. So, \( z = \frac{x - \mu}{\sigma} = \frac{36 - 50}{7} = -2 \) The z-score of -2 means that 36 is 2 standard deviations below the mean. Show more…
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