00:01
The question has been provided with aqueous solution of few compounds which are naclo4, feclo4 twice, rboh aqueous, hbr aqueous, na2s aqueous.
00:37
And we are asked to assume that all the solutions have equal concentration and with this information we are asked to write the order of these compounds in highest ph to lowest ph.
01:07
Let's solve the question.
01:11
So before that we will understand that for acidic solution, for acidic solution the ph is less than 7.
01:30
For basic solution ph is greater than 7 and for neutral solution ph is equal to 7.
02:01
So if you take the list we can clearly see that hbr among all the compounds is a strong acid.
02:16
And if you take rboh this solution is strong base.
02:30
So this will have the lowest ph that is hbr and rboh will have the highest ph because it is a basic solution for basic solution ph is greater than 7.
02:52
Therefore highest ph is 7 and for acidic solution ph is less than 7.
02:57
Therefore lowest ph for hbr.
02:59
So we have find out two extreme compounds.
03:01
Now we have to fill the in between compounds.
03:06
Then next we will go on to naclo4.
03:19
So if this when dissolved in water it will split as na plus plus clo4 minus.
03:27
So this na plus has come from naoh and this clo4 has come from hclo4.
03:33
Therefore we can say that this salt is a combination of strong acid that is hclo4 acid and strong base which is naoh.
03:58
Since acid and base concentration or acid and base quantity is same here therefore we can say that the ph of this aqueous solution is equal to 7.
04:08
It is a neutral compound.
04:12
Next we will see the next compound that is na2s.
04:16
So if this dissolved in water it will release to na plus plus s2 minus...