Assuming pitot tubes are not placed directly on the nose of...

Name: assuming pitot tubes are not placed directly on the nose of an aircraft explain why the pitot tube must extend a finite distance away from the aircraft surface to produce accurate measuremen 71735
Uploaded: 2021-08-24T11:12:18-08:00
Duration: 2 min 11 s
Channel: Prabhu Ramji
Description: assuming pitot tubes are not placed directly on the nose of an aircraft explain why the pitot tube must extend a finite distance away from the aircraft surface to produce accurate measuremen 71735

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A pitot tube (Fig. $14-48$ ) is used to determine the airspeed of an airplane. It consists of an outer tube with a number of small holes $B$ (four are shown) that allow air into the tube; that tube is connected to one arm of a U-tube. The other arm of the U-tube is connected to hole $A$ at the front end of the device, which points in the direction the plane is headed. At $A$ the air becomes stagnant so that $v_{A}=0 .$ At $B,$ however, the speed of the air presumably equals the airspecd $v$ of the plane. (a) Use Bernoulli's equation to show that $$ v=\sqrt{\frac{2 \rho g h}{\rho_{\text {ar }}}} $$ where $\rho$ is the density of the liquid in the $U$ -tube and $h$ is the difference in the liquid levels in that tube. (b) Suppose that the tube contains alcohol and the level difference $h$ is $26.0 \mathrm{~cm}$. What is the plane's speed relative to the air? The density of the air is $1.03 \mathrm{~kg} / \mathrm{m}^{3}$ and that of alcohol is $810 \mathrm{~kg} / \mathrm{m}^{3}$

a-pitot-tube-fig-14-48-is-used-to-determine-the-airspeed-of-an-airplane-it-consists-of-an-outer-tu-3

A pitot tube (Fig. 14-48) is used to determine the airspeed of an airplane. It consists of an outer tube with a number of small holes $B$ (four are shown) that allow air into the tube; that tube is connected to one arm of a U-tube. The other arm of the U-tube is connected to hole $A$ at the front end of the device, which points in the direction the plane is headed. At $A$ the air becomes stagnant so that $v_{A}=0$. At $B$, however, the speed of the air presumably equals the airspeed $v$ of the plane. (a) Use Bernoulli's equation to show that $$ v=\sqrt{\frac{2 \rho g h}{\rho_{\text {air }}}} \text { , } $$ where $\rho$ is the density of the liquid in the $\mathrm{U}$ -tube and $h$ is the difference in the liquid levels in that tube. (b) Suppose that the tube contains alcohol and the level difference $h$ is $26.0 \mathrm{~cm}$. What is the plane's speed relative to the air? The density of the air is $1.03 \mathrm{~kg} / \mathrm{m}^{3}$ and that of alcohol is $810 \mathrm{~kg} / \mathrm{m}^{3}$.

Pitot Tube A pitot tube (Fig. $15-49$ ) is used to determine the airspeed of an airplane. It consists of an outer tube with a number of small holes $B$ (four arc shown) that allow air into the tube; that tube is connected to one arm of a U-tube. The other arm of the Utube is connected to hole $A$ at the front end of the device, which points in the direction the plane is headed. At $A$ the air becomes stagnant so that $v_{A}=0 .$ At $B$, however, the speed of the air presumably equals the airspeed $v$ of the aircraft. (a) Use Bernoulii's equation to show that $$ v=\sqrt{\frac{2 \rho g h}{\rho_{\text {air }}}} $$ where $\rho$ is the density of the liquid in the U-tube and $h$ is the difference in the fluid levels in that tube. (b) Suppose that the tube contains alcohol and indicates a level difference $h$ of $26.0 \mathrm{~cm}$. What is the plane's speed relative to the air? The density of the air is $1.03 \mathrm{~kg} / \mathrm{m}^{3}$ and that of alcohol is $810 \mathrm{~kg} / \mathrm{m}^{3}$

Transcript

00:02 This problem covers the concept of bernoulli equation.

00:05 Using the bernouill equation we can write the pressure at a plus half of the density of air into the speed of air at k squared equals the pressure at b plus half of the density of air into b b squared.

00:28 Now substitute the values, the speed of air at a is 0.

00:33 So we can neglect this term.

00:37 And from this we can write the pressure a minus the pressure at b equals half of the density of air into v squared.

00:50 Let's say this as equation 1.

00:52 Now using the manometer, the pressure difference b .a minus bb equals the density of the liquid inside the manometer into row g h...

Question

Assuming pitot tubes are not placed directly on the nose of an aircraft, explain why the pitot tube must extend a finite distance away from the aircraft surface to produce accurate measurements of the aircraft velocity.

Question

Assuming pitot tubes are not placed directly on the nose of an aircraft, explain why the pitot tube must extend a finite distance away from the aircraft surface to produce accurate measurements of the aircraft velocity.

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