00:02
Question is assuming that only the listed gases are present.
00:06
What would be the more fraction of oxygen? that's for the following situations.
00:12
So we are going to discuss how can we calculate the mole fraction of the oxygen in each of the following cases.
00:19
In the first question we have mass of nitrogen.
00:25
Mass of nitrogen is given that is the 4 .53 grams.
00:31
So, mole of nitrogen will be what? mass by molar mass, so mass is the 4 .53 gram.
00:39
Molar mass of n2 is the 28 gram per mole.
00:44
That will come out here, 0 .16.
00:49
Mass of oxygen is given in the question, that is the 3 .61 gram.
00:55
So mole of oxygen will be what? 3 .61 divided by 32 gram per mole.
01:02
That will come out here 0 .11.
01:05
Now we have to calculate more fraction of oxygen.
01:08
So more fraction is equal to more of o2 divide by mole of o2 plus more of n2.
01:16
So it will be equal to 0 .11, 0 .11 plus 0 .16.
01:22
That will comes out here 0 .407.
01:26
Correct.
01:29
So in the b part, we have a gas sample of 2 .3.
01:36
Atmosphere of oxygen gas.
01:39
So pressure of oxygen is given 2 .31 atmosphere.
01:45
And the pressure of hydrogen gas is given 3 .75.
01:51
Correct.
01:52
As we know that from the ideal gas equation, pressure is directly proportional to mole of gas.
01:58
So pressure will be equal to more of o2, mole of so now we have to calculate mole fraction of oxygen that will be equal to more of o2 divided by a more of o2 plus mole of hydrogen.
02:17
So 2 .31 divided by 2 .31 plus 3 .75.
02:25
So it will come out here 0 .38, correct? okay.
02:34
Now 28 a part.
02:39
Have a sample of gas contains 6 .43 mole.
02:44
So more of gas is given 6 .43.
02:53
Temperature is given 37 .8 degrees centigrade.
02:59
So when we convert it into kelvin, then it will comes out 310 .8 kelvin.
03:07
Volume is given 3 .61 liter.
03:11
Correct.
03:12
So pressure we have to calculate.
03:14
Pressure we have to calculate in the atmosphere.
03:21
So from the ideal gas equation, we know that pv equal to nrp, r is the gas constant.
03:29
So we have to calculate volume is 3 .61 equal to 6 .43 into 1 by 12, temperature, 310 .8.
03:42
So pressure will come out here, 46 .13 atmosphere.
03:49
Now for the b part we have a sample of gas contains 6 .43 moles of gas at 37 .8 degrees centigrade in a volume of 3 .61 liter...