Assuming that $v_s = 10 \cos(8t + 45^\circ)$, find the average power delivered to each of the passive elements.
Added by Joseph G.
Close
Step 1
The instantaneous power is given by the formula P = VI, where V is the voltage across the element and I is the current flowing through the element. For a passive element, the voltage and current are related by Ohm's Law: V = IR, where R is the resistance of the Show more…
Show all steps
Your feedback will help us improve your experience
Darshan Maheshwari and 88 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Determine the amount of power absorbed or supplied by the element in Fig. P1.20 if (a) $V_{1}=9 \mathrm{V}$ and $I=2 \mathrm{A}$ (b) $V_{1}=9 \mathrm{V}$ and $I=-3 \mathrm{A}$ (c) $V_{1}=-12 \mathrm{V}$ and $I=2 \mathrm{A}$ (d) $V_{1}=-12 \mathrm{V}$ and $I=-3 \mathrm{A}$
In the $L R C$ circuit of Fig. $30-19$, suppose $I=I_{0} \sin \omega t$ and $V=V_{0} \sin (\omega t+\phi) .$ Determine the instantaneous power dissipated in the circuit from $P=I V$ using these equations and show that on the average, $\bar{P}=\frac{1}{2} V_{0} I_{0} \cos \phi$, which confirms Eq. $30-30$.
Prabhakar K.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD