At 25.0°C, the Henry's Law constant for phosphine (PH3) gas in water is 8.1*10^−3 M/atm. Calculate the mass in grams of PH3 gas that can be dissolved in 675 mL of water at 25.0°C and a PH3 partial pressure of 4.58 atm. Round your answer to 2 significant digits. g=
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1 \times 10^{-3} \, \text{M/atm} \times 4.58 \, \text{atm}\] \[C = 0.03798 \, \text{M}\] Show more…
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