00:01
Hello students, in this question the solubility product of the potassium per chloride has been given and the mass of the potassium per chloride has been given and this has been reacted with the sodium per chloride whose concentration and the volume has been given.
00:12
We have to find out the concentration of the potassium ion at the equilibrium condition.
00:18
So at first we want to know the dissociation equation for the potassium per chloride.
00:22
The potassium per chloride will be dissociate into potassium ion plus chloride ion.
00:28
So based on this we can give the solubility product.
00:33
The ksp is given by the ionic product of water that is the product of concentration of the potassium ion into chloride per chloride ion.
00:42
So based on this now we are going to write the dissociation equation for the sodium per chloride.
00:49
The sodium per chloride will be dissociate into sodium ion plus per chloride ion.
00:56
So here the concentration of the sodium per chloride is 0 .10 m.
01:02
So here the sodium per chloride and the per chloride ion are in 1 is to 1 ratio therefore its concentration will be equal that is 0 .10 m.
01:11
So the concentration of the per chloride ion in this case will be equal to 0 .10 m...