Question

At 300 K, for a diode current of 1 mA, a certain germanium diode requires a forward bias of 0.1435 V, while a certain silicon diode requires a forward bias of 0.718 V. Under the condition stated above, find the closest approximation of the ratio of reverse saturation current in germanium diode to that of silicon diode. (For silicon n=2 and for germanium n=1) The answer is 4*10^3.

Name: at 300 k for a diode current of 1 ma a certain germanium diode requires a forward bias of 01435 v where a certain silicon diode requires a forward bias if 0718 v under the condition stated a 86537
Uploaded: 2022-12-13T07:33:21-08:00
Duration: 4 min 42 s
Channel: Sri K
Description: at 300 k for a diode current of 1 ma a certain germanium diode requires a forward bias of 01435 v where a certain silicon diode requires a forward bias if 0718 v under the condition stated a 86537

          At 300 K, for a diode current of 1 mA, a certain germanium diode requires a forward bias of 0.1435 V, while a certain silicon diode requires a forward bias of 0.718 V. Under the condition stated above, find the closest approximation of the ratio of reverse saturation current in germanium diode to that of silicon diode. (For silicon n=2 and for germanium n=1)
The answer is 4*10^3.

Added by Paul B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

12/13/2022

Step 1

1435 \) V - Forward bias voltage for silicon diode \( V_{Si} = 0.718 \) V - Ideality factor for germanium \( n_{Ge} = 1 \) - Ideality factor for silicon \( n_{Si} = 2 \) Show more…

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At 300 K, for a diode current of 1 mA, a certain germanium diode requires a forward bias of 0.1435 V, while a certain silicon diode requires a forward bias of 0.718 V. Under the condition stated above, find the closest approximation of the ratio of reverse saturation current in germanium diode to that of silicon diode. (For silicon n=2 and for germanium n=1) The answer is 4*10^3.