Question

At a certain temperature, the equilibrium constant K for the following reaction is 2.06×10??: Cl?(g) + CHCl?(g) ? HCl(g) + CCl?(g) Use this information to complete the following table. Suppose a 31. L reaction vessel is filled with 1.9 mol of Cl? and 1.9 mol of CHCl?. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little Cl? and CHCl?. There will be very little HCl and CCl?. Neither of the above is true. What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. HCl(g) + CCl?(g) ? Cl?(g) + CHCl?(g) K = What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. 3 Cl?(g) + 3CHCl?(g) ? 3 HCl(g) + 3CCl?(g) K =

          At a certain temperature, the equilibrium constant K for the following reaction is 2.06×10??:
Cl?(g) + CHCl?(g) ? HCl(g) + CCl?(g)
Use this information to complete the following table.
Suppose a 31. L reaction vessel is filled with 1.9 mol of Cl? and
1.9 mol of CHCl?. What can you say about the composition of the
mixture in the vessel at equilibrium?
There will be very little Cl? and CHCl?.
There will be very little HCl and CCl?.
Neither of the above is true.
What is the equilibrium constant for the following reaction?
Round your answer to 3 significant digits.
HCl(g) + CCl?(g) ? Cl?(g) + CHCl?(g)
K = 
What is the equilibrium constant for the following reaction?
Round your answer to 3 significant digits.
3 Cl?(g) + 3CHCl?(g) ? 3 HCl(g) + 3CCl?(g)
K =
        
Show more…
At a certain temperature, the equilibrium constant K for the following reaction is 2.06×10??:
Cl?(g) + CHCl?(g) ? HCl(g) + CCl?(g)
Use this information to complete the following table.
Suppose a 31. L reaction vessel is filled with 1.9 mol of Cl? and
1.9 mol of CHCl?. What can you say about the composition of the
mixture in the vessel at equilibrium?
There will be very little Cl? and CHCl?.
There will be very little HCl and CCl?.
Neither of the above is true.
What is the equilibrium constant for the following reaction?
Round your answer to 3 significant digits.
HCl(g) + CCl?(g) ? Cl?(g) + CHCl?(g)
K = 
What is the equilibrium constant for the following reaction?
Round your answer to 3 significant digits.
3 Cl?(g) + 3CHCl?(g) ? 3 HCl(g) + 3CCl?(g)
K =

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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At a certain temperature, the equilibrium constant K for the following reaction is 2.06 x 10^(-7): Cl2(g) + CHCl3(g) ⇌ HCl(g) + CCl4(g) Use this information to complete the following table. 1. Suppose a 31. L reaction vessel is filled with 1.9 mol of Cl2 and 1.9 mol of CHCl3. What can you say about the composition of the mixture in the vessel at equilibrium? - There will be very little Cl2 and CHCl3. - There will be very little HCl and CCl4. - Neither of the above is true. 2. What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. - X HCl(g) + CCl4(g) ⇌ Cl2(g) + CHCl3(g) 3. What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. - 3 Cl(g) + 3 CHCl3(g) ⇌ 3 HCl(g) + 3 CCl4(g)
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At a certain temperature, the equilibrium constant K for the following reaction is 9.58 x 10^8: Br2(g) + OCl2(g) ⇌ BrOCl(g) + BrCl(g) Use this information to complete the following table. Suppose a 11. L reaction vessel is filled with 0.42 mol of Br2 and 0.42 mol of OCl2. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little Br2 and OCl2. There will be very little BrOCl and BrCl. Neither of the above is true. What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. BrOCl(g) + BrCl(g) ⇌ Br2(g) + OCl2(g) What is the equilibrium constant for the following reaction? Round your answer to 3 significant digits. 2 Br2(g) + 2 OCl2(g) ⇌ 2 BrOCl(g) + 2 BrCl(g)

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Transcript

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00:01 For this given reaction, we know the equilibrium constant.
00:05 Cl2 gas reacts with c, h .c .l .3 gas to produce h .c .l.
00:18 As a gas and carbon tetrachloride as a gas.
00:28 And k is equal to 4 .73 times 10 to the negative 11.
00:37 Because it's so small, we're going to get hardly any product at equilibrium.
00:44 So it mentions that we have a 12 -liter vessel.
00:48 We had 1 .7 moles of this and 1 .7 moles of this.
00:54 And we're asked, what can we say about the composition of the mixture in the vessel? well, we're going to have mostly 1 .7 and 1 .7.
01:02 We're going to make hardly any of these two.
01:05 So there will be little cl2...
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