Question

At a certain temperature, the equilibrium constant, Kc, for this reaction is 53.3. H$_2$(g) + I$_2$(g) \iff 2HI(g) K$_c$ = 53.3 At this temperature, 0.300 mol H$_2$ and 0.300 mol I$_2$ were placed in a 1.00 L container to react. What concentration of HI is present at equilibrium? [HI] =

          At a certain temperature, the equilibrium constant, Kc, for this reaction is 53.3.
H$_2$(g) + I$_2$(g) \iff 2HI(g)
K$_c$ = 53.3
At this temperature, 0.300 mol H$_2$ and 0.300 mol I$_2$ were placed in a 1.00 L container to react. What concentration of HI is
present at equilibrium?
[HI] =
        
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At a certain temperature, the equilibrium constant, Kc, for this reaction is 53.3.
H2(g) + I2(g) 2HI(g)
Kc = 53.3
At this temperature, 0.300 mol H2 and 0.300 mol I2 were placed in a 1.00 L container to react. What concentration of HI is
present at equilibrium?
[HI] =

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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At a certain temperature, the equilibrium constant, K_(c), for this reaction is 53.3 . H_(2)(g)+I_(2)(g)⇌2HI(g),K_(c)=53.3 At this temperature, 0.300molH_(2) and 0.300molI_(2) were placed in a 1.00L container to react. What concentration of HI is present at equilibrium? [HI]= [HI]= present at equilibrium? Hg)+I(g)=2HI(g) K=53.3 At a certain temperature, the equilibrium constant, Kc , for this reaction is 53.3
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Transcript

-
00:01 Hi in this question we have given this reaction we need to find out concentration of hi in equilibrium kc value is given initially 0 .8080 mole h2 and i2 is present in the container container volume is 1 liter so if i is this that is at initial phase h i or number of moles of h i was 0 if we consider change is minus x it is also minus x it will be 2x at equilibrium it will be 0 .80 minus x 0 .80 minus x and this is 2x and concentration will be divided by volume that is 1 is also 1 1 as concentration is equal with number of modes by volume so kc can be written as concentration of h i to the power 2 by concentration of h2 into concentration of i 2 kc value is given 53 .3 h .i we need to find out.
01:06 It is also given 2x to the power 2 by 0 .80 minus x whole square.
01:15 So 0 .64 minus 1 .6x plus x plus x square by taking this value to here equal to 4x square by 53 .3 .3...
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