00:01
In the given equation, the equilibrium reaction of h2 and i2 is given as h2 plus i2 and this is in equilibrium with 2hi.
00:17
The initial pressure of h2 gas is given 1 .62 atmosphere and the initial pressure of i2 gas is given 4 .34 atmosphere.
00:31
At equilibrium, the pressure of h .i is given which is equal to 1 .443 atmosphere.
00:41
We have to find the kp value that is equilibrium constant value for this equation.
00:48
So we have to write the equation again, that is h2 plus i2 and this will be in equilibrium with 2hi.
01:01
So the initial pressure will be 1 .62, 4 .34 and initially no product is present, so it will be 0.
01:14
Now we have to write the change.
01:16
So for this case the change will be minus x, this is also minus x and this will be plus 2x as the coefficient of h .i is 2.
01:26
So at equilibrium the pressure will be 1 .62 minus x.
01:32
This is 4 .34 minus x and this is 2x.
01:38
So this is the ice table for this equation.
01:41
Now in the given question it is said that at equilibrium the pressure of h i is equal to 1 .443 atmosphere...