00:01
Hello everyone, so the question says here that a particular temperature, the solubility of oxygen in water is given solubility of oxygen in water solubility of oxygen in water is given which is 0 .5 0 .05 0 .0.
00:34
Solubility 05 and the partial pressure and the partial pressure and when the partial pressure was 0 .12 atmosphere.
00:47
So the partial pressure was 0 .1 2 atmosphere.
00:55
So we have been asked that what will be the solubility when the partial pressure of oxygen is 0 .36 atmosphere.
01:05
That means we have to find out the solubility when the partial pressure is equal to 0 .36.
01:14
80m so according to henry's law according to according to henry's law henry's constant that is kh is equal to solubility solubility divided by partial pressure solubility divided by partial pressure so in the first case, as we have been given the solubility of oxygen, which is 0 .05, and the partial pressure is also given, that means we can calculate henry's constant from this.
02:24
So, the henry's constant, kh equals to 0 .05 divided by 0 .12, that gives 0 .417.
02:42
So that's the value of henry's constant.
02:45
Now again, as we have the value of henry's constant here, for the second case, for the second case where we know the value of partial pressure, we have calculated the value of henry's constant, then we can calculate the solubility...