At a point on level ground 50 feet from the base of a vertical tower, the angle of elevation to the top of the tower is 25°20'. Find the height of the tower to the nearest tenth of a foot. Show all work.
Added by Lauren M.
Step 1
In this case, the opposite side is the height of the tower (which we're trying to find), and the adjacent side is the distance from the base of the tower to the point on the ground, which is 50 feet. Show more…
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Height of a tower From a point $P$ on level ground, the angle of elevation of the top of a tower is $26^{\circ} 50^{\prime} .$ From a point 25.0 meters closer to the tower and on the same line with $P$ and the base of the tower, the angle of elevation of the top is $53^{\circ} 30^{\prime} .$ Approximate the height of the tower.
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