At an axial load of 22 kN, a 15-mm-thick Ă— 40-mm-wide polyimide polymer bar elongates 4.1 mm while the bar width contracts 0.15 mm. The bar is 270 mm long. At the 22 kN load, the stress in the polymer bar is less than its proportional limit. Determine Poisson's ratio.
Added by Katherine A.
Step 1
The bar has a thickness of 15 mm and a width of 40 mm. \[ A = \text{thickness} \times \text{width} = 15 \, \text{mm} \times 40 \, \text{mm} = 600 \, \text{mm}^2 \] Show more…
Show all steps
Close
Your feedback will help us improve your experience
Mauya Mitchell and 70 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
thoughtful
Gokul R N.
At an axial load of 25 kN, a 45-mm-wide by 20-mm-thick polyimide polymer bar elongates 3.1 mm while the bar width contracts 0.29 mm. The bar is 170 mm long. At the 25-kN load, the stress in the polymer bar is less than its proportional limit. Determine (a) the modulus of elasticity. (b) Poisson's ratio. (c) the change in the bar thickness. Answers: (a) E = GPa (b) v = (c) Δthickness = mm
Madhur L.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD